2x^2-990x-500000=0

Solution for 2x^2-990x-500000=0 equation:

2x^2-990x-500000=0

a = 2; b = -990; c = -500000;
Δ = b2-4ac
Δ = -9902-4·2·(-500000)
Δ = 4980100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4980100}=\sqrt{100*49801}=\sqrt{100}*\sqrt{49801}=10\sqrt{49801}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-990)-10\sqrt{49801}}{2*2}=\frac{990-10\sqrt{49801}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-990)+10\sqrt{49801}}{2*2}=\frac{990+10\sqrt{49801}}{4}
$